Question 748655
log(x+4)-log6=1
log[(x+4)/6] = 1
(x+4)/6 = 10^1
x+4 = 60
x = 56
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18) log(x-1)^2=log(-5x-1)
(x-1)^2 = -5x-1
x^2 -2x + 1 = -5x -1
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x^2 +3x = 0
x(x+3) = 0
x = 0 or x = -3
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Cheers,
Stan H.