Question 748571
Let the smallest integer be x, then the middle is x+1 and the largest is x+2.

5 times the 2nd equals twice the sum of the 1st and 3rd:

{{{5(x+1)=2(x+(x+2))}}}

{{{5x+5=2(2x+2)}}}

{{{5x+5=4x+4}}}

{{{x+5=4}}}

{{{x= -1}}}

The other numbers are x+1 and x+2, so they are 0 and 1.