Question 65026
Having difficulty with two problems: 
2^(x+3)=5^x 
Take the log of both sides to get:
(x+3)log2 = xlog5
Distribute to get:
(log2)x + 3log2 = xlog5
Get the x-terms together as follows:
(log2-log5)x=-3log2
Evaluate to get:
-0.39794..x=-0.903089987..
Divide to get:
x=2.269...
-----------------
and 
10e^(3x-7)=5 
Divide by 10 to get:
e^(3x-7)=(1/2)
Take the natural log of both sides to get:
3x-7=ln(1/2)
3x=-0.693147...+7
3x=6.30685...
x=2.10228...
Cheers,
Stan H.