Question 748288
we will denote log base 5 as log5

{{{5^(x-1)= 5^x-5}}}


{{{5^(x-1)-5^(x-1)+5= 5^x-5^(x-1)-5+5}}}


{{{5^x-(5^x)/5= 5}}}


{{{5^x*(1-1/5)=5}}}


{{{5^x=5/(4/5)}}}


{{{5^x=25/4}}}


{{{
log5(5^x)=log5(25/4)
}}}


{{{
x=log5(25)-log5(4)=2-log5(4)
}}}




:)