Question 747903
In a jar of ten beads, seven are red and three are blue. A bead is drawn from the jar five times with replacement. What is the probability of seeing exactly 2 blue beads?
---
"With replacement" implies you have a binomial problem.
------
n = 5 and p(blue) = 3/10
----
P(x = 2) = 5C2*0.3^2*0.7^3 = binompdf(5,0.3,2) = 0.3087
====================
Cheers,
Stan H.
====================