Question 747869

to graph {{{y= -(2/3)x - 2 }}} find two points and draw a line through

{{{x}}}|{{{y}}}

{{{-3}}}|{{{0}}}.....{{{y= -(2/3)(-3) - 2=(-2)(-1)-2=2-2=0 }}}

{{{0}}}|{{{-4}}}.....{{{y= -(2/3)0 - 2=-2 }}}

plot the points: ({{{3}}},{{{-4}}}) and ({{{0}}},{{{-2}}})


{{{drawing( 600, 600, -10, 10, -10, 10,circle(0,-2,0.2), circle(-3,0,0.2), graph( 600, 600, -10, 10, -10, 10, -(2/3)x - 2)) }}}