Question 8310
{{{b / (b - 1)}}}  +  {{{2b / (b^2 - 1)}}}


={{{b / (b - 1)}}}  +  {{{2b / (b-1)(b+1))}}}


={{{(b)(b+1) / (b - 1)(b+1)}}}  +  {{{2b / (b-1)(b+1))}}}


={{{(b^2+b) / (b - 1)(b+1)}}}  +  {{{2b / (b-1)(b+1))}}}


={{{(b^2+3b) / (b - 1)(b+1)}}}


={{{(b)(b+3) / (b - 1)(b+1)}}}


={{{(b)(b+3) / (b^2-1)}}}