Question 747735
We are given

The longer leg of a right triangle is 2 cm more than twice the shorter leg. Find the measure of each leg of the triangle with the smallest possible area.

Area = 1/2 * base * height

let x be the shorter leg and 2x+2 is the longer leg

then Area = 1/2*x*2(x+1) = x^2+x

Assuming values of x are whole numbers, then

if x = 1cm, then Area = 2cm^2 and the longer leg is 4cm