Question 65009
1.ariel has $5.50 in dimes and quarters. she has 8 more quarters than dimes. How many quaters does she have? 
Let # of dimes be x : value of these is 10x cents
Number of quarters is "x+8"; value of these is 25(x+8)=25x+200 cents
EQUATION:
value + value = 550 cents
10x+25x+200=550
35x=350
x=10 (number of dimes)
x+8=18 (number of quarters)
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2. tenisha and dameisha have the same number of coins. Tenisha has only dimes and dameisha has only quaters. if damiesha has $1.80 more than tenisha does, how much does each have?
Tenisha DATA:
# of dimes is "x"; value of these is 10x cents
Dameisha DATA:
# of quarters is "x"; value of these is 25x cents
EQUATION:
Tenisha value + 180 = damiesha value
10x+180=25x
15x=180
x=12
Tenisha has 12*10=$1.20
Dameisha has 12*25=$3.00
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Cheers,
Stan H.