Question 747677
There are three consecutive numbers. When the largest one is squared, it is equal to 18 more than 9 times the smallest number. 

 Please explain thoroughly and clearly, as I am in a deep fix. Can you also give me the three consecutive numbers? 
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1st: x-1
2nd: x
3rd: x+1
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Equation:
(x+1)^2 = 9(x-1)+18
x^2 + 2x + 1 = 9x-9+18
x^2 -7x -8 = 0
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(x-8)(x+1) = 0
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Positive solution:
x = 8
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1st: x-1 = 7
2nd: x = 8
3rd: x+1 = 9
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Cheers,
Stan H.