Question 746329
step by step write the conic section in standard form. 
y^2-8x-4y+4=0
y^2-4y-8x+4=0
complete the square:
(y^2-4y+4)-4-8x+4=0
(y-2)^2=8x
This is an equation of a parabola that opens rightward with vertex at (0,2)
Its basic form: (y-k)^2=4p(x-h), (h,k)=(x,y) coordinates of the vertex