Question 747637
Solve the following system of equations: 
	x –2y+z=6
	2x+y –3z= –3
	x –3y+3z=10
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Multiply egn 1 & 3 by 2.
Subtract eqn 1 from eqn 2 --> an eqn in y & z
Subtract eqn 1 from eqn 3 --> an eqn in y & z
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That leaves 2 eqns in y & z
Can you finish it?
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I would use determinants.  You familiar with those?