Question 747332
Suppose you have data that is normally distributed with a mean of 36 and a standard deviation of 7 find the percent of data between 29 and 57
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z(57) = (57-36)/7 = 3
z(29) = (29-36)/7 = -1
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P(29<= x <=57) = P(-1<= z <=3) = normalcdf(-1,3) = 0.8400
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Cheers,
Stan H.
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