Question 747351
Lengthwise:  2*pi*r=8&1/2
r=(8&1/2)/(2*pi)
volume=pi*r^2*11
volume=pi*((8&1/2)/(2*pi))^2*11
volume={{{((8&1/2)^2/(4*pi))*11}}}
{{{highlight(794.75/(4*pi))}}} which is smaller than widthwise way.


Widthwise: 2*pi*r=11
r=11/(2*pi)
volume=pi*r^2*(8&1/2)
volume=pi*(11/(2*pi))^2(8&1/2)
volume={{{(11^2/(4*pi))(8&1/2)}}}
{{{highlight(1028.5/(4*pi))}}}, which is bigger than the lengthwise way.