Question 747328
Let w be the width.  
Then the length can be represented by 2w-3 (3 less than twice the width)

The area of a rectangle is given by:

{{{A=l*w}}}

Now, plug in for A, l and w.

{{44=(2w-3)(w)}}}

Distribute,

{{{44=2w^2-3w}}}

Subtract 44 from both sides:

{{{0=2w^2-3w-44}}}

Since I'm not sure how to show you the regrouping hourglass method on here, I've used the quadratic solver from this site to get to the solution for you.  You can always use the quadratic formula when solving quadratics.  See below the graph for the final explanation and answer.

*[invoke quadratic "x", 2, -3, -44 ]

Since the width cannot be a negative number, you can throw out the w=-4 solution.

Thus, the width is 5.5 feet.  

The length was 3 feet less than twice the width.  

{{{l=2w-3}}} 

Plug in 5.5 for w:

{{{l=2(5.5)-3}}} 

Distribute:

{{{l=11-3}}} 

Simplify:

{{{l=8}}}

Finally, you have both.  l= 8ft and w= 5.5ft