Question 747262
Use the quadratic formula to solve for x


{{{x = (-b+-sqrt(b^2-4ac))/(2a)}}}


{{{x = (-(9)+-sqrt((9)^2-4(4)(7)))/(2(4))}}} Plug in {{{a = 4}}}, {{{b = 9}}}, {{{c = 7}}}


{{{x = (-9+-sqrt(81-(112)))/(8)}}}


{{{x = (-9+-sqrt(-31))/8}}}


{{{x = (-9+sqrt(-31))/8}}} or {{{x = (-9-sqrt(-31))/8}}}


{{{x = (-9+i*sqrt(31))/8}}} or {{{x = (-9-i*sqrt(31))/8}}}


So the two solutions are {{{x = (-9+i*sqrt(31))/8}}} or {{{x = (-9-i*sqrt(31))/8}}}