Question 747311
On the daily run of an express bus, the average number of passengers is 48. The
standard deviation is 3. Assume the variable is normally distributed. 
Find the probability that the bus will have 
a) fewer than 42?
z(42) = (42-48)/3 = -2
P(x < 42) = P(z < -2) = 0.0228
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b) more than 48?
z(48) = (48-48)/3 = 0
P(x > 48) = P(z > 0) = 0.5000
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Cheers,
Stan H.
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