Question 64938
:
{{{3/(x^2+4x+3) - 1/(x^2-9)}}} = {{{3/((x+3)(x+1)) - 1/((x-3)(x+3))}}}=
:
The common denominators will be the three factors:
{{{(3(x-3) - 1(x+1))/(x+3)(x+1)(x-3))}}} = {{{(3x - 9 - x - 1)/(x+3)(x+1)(x-3))}}} = {{{(2x -10)/(x+3)(x+1)(x-3))}}} is about as simple as you can get it