<PRE><B>Question 746863</B>
the formulae to calulate the equation of line is

           y-y1 = y2-y1/x2-x1 (x-x1)


                            where  x1,y1  is  1,5
                             and   x2,y2  is  4,11

           y-5 = 11-5/4-1 (x-1)

               = 6/3 (x-1)
               = 2 (x-1)
           y-5 = 2x - 2
    hence, 2x-y+3=0 is required equation.

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