Question 747071
log base 6 X + log base 6 X-3=2 
the answer is 7.365 
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{{{log(6,(x))+log(6,(x-3))=2}}}
{{{log(6,(x)(x-3))=2}}}
convert to exponential form: base(6) raised to log of number(2)=number((x)(x-3))
6^2=x^2-3x
x^2-3x-36=0
solve for x by quadratic formula:
x≈-4.68 (reject, x>0)
or 
x≈7.684