Question 746974

Use the quadratic formula to solve for x


{{{x = (-b+-sqrt(b^2-4ac))/(2a)}}}


{{{x = (-(28)+-sqrt((28)^2-4(10)(16)))/(2(10))}}} Plug in {{{a = 10}}}, {{{b = 28}}}, {{{c = 16}}}


{{{x = (-28+-sqrt(784-(640)))/(20)}}}


{{{x = (-28+-sqrt(144))/20}}}


{{{x = (-28+sqrt(144))/20}}} or {{{x = (-28-sqrt(144))/20}}}


{{{x = (-28+12)/20}}} or {{{x = (-28-12)/20}}}


{{{x = -16/20}}} or {{{x = -40/20}}}


{{{x = -4/5}}} or {{{x = -2}}}


The two solutions are {{{x = -4/5}}} or {{{x = -2}}}