Question 64967
If you need to write this as a single logarithm, this is what you do:

{{{4loga(8x^4)-(1/8)loga(6x+7)}}}
{{{loga((8x^4)^4)-loga((6x+7)^(1/8))}}}
{{{loga(8^4*x^16)-loga((6x+7)^(1/8))}}}
{{{loga((4096*x^16)/(6x+7)^(1/8))}}}
Happy Calculating!!!