Question 746824
log3(x+4) + Log3(x-2)=3
{{{log(3,(x+4))+log(3,(x-2))=3}}}
{{{log(3,((x+4)(x-2)))=log(3(27))}}}
(x+4)(x-2)=27
x^2+2x-8=27
x^2+2x-35=0
(x+7)(x-5)=0
x=-7 (reject, (x+4)>0)
or
x=5