Question 746932
Complete the square of the following problem: 2x^2 = 4x - 5
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I think you mean solve for x by completing the square.
{{{2x^2 = 4x - 5}}}
{{{2x^2 - 4x = - 5}}}
{{{x^2 - 2x = -5/2}}}
{{{x^2 - 2x + 1 = -5/2 + 1 = -3/2}}}
{{{(x-1)^2 = -3/2}}}
{{{x-1 = sqrt(-3/2)}}}
{{{x = 1 + i*sqrt(6)/2}}}
{{{x = 1 - i*sqrt(6)/2}}}
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Same as your answers, I took the fraction out of the radical.