Question 746904
First obtain your y coordinate by
substituting x = -2 into f(x)
f(x) = -2(-2)^2 + 3(-2) - 2
     =  -8 -6 -2
     = -16      Coords are: {-2, -16}

 Differentiate f(x)
    f'(x) = - 4x + 3
Substitute x = -2 into f'(x)
     -4(-2) + 3  = 11  (gradient)

  Using y - b = m(x - a)
        y + 16 = 11(x + 2)
            y = 11x + 22 - 16
            y = 11x + 6