<PRE><B>Question 746780</B>
&lt;pre&gt;
50x&lt;sup&gt;5&lt;/sup&gt;-75x&lt;sup&gt;4&lt;/sup&gt;+40x&lt;sup&gt;3&lt;/sup&gt;-60x&lt;sup&gt;2&lt;/sup&gt;+8x-12

This has 6 terms, so we group the odd degree 
terms together and the even degree terms 
together:

(50x&lt;sup&gt;5&lt;/sup&gt;+40x&lt;sup&gt;3&lt;/sup&gt;+8x)+(-75x&lt;sup&gt;4&lt;/sup&gt;-60x&lt;sup&gt;2&lt;/sup&gt;-12)

We can factor 2x out of the first parentheses
and -3 out of the second parentheses:

2x(25x&lt;sup&gt;4&lt;/sup&gt;+20x&lt;sup&gt;2&lt;/sup&gt;+4)-3(25x&lt;sup&gt;4&lt;/sup&gt;+20x&lt;sup&gt;2&lt;/sup&gt;+4)

Now we can factor (25x&lt;sup&gt;4&lt;/sup&gt;+20x&lt;sup&gt;2&lt;/sup&gt;+4) out of each
and leave 2x and -3 to go in a parentheses:

(25x&lt;sup&gt;4&lt;/sup&gt;+20x&lt;sup&gt;2&lt;/sup&gt;+4)(2x-3)

We can also factor the trinomial in the first
parentheses and get:

(5x&lt;sup&gt;2&lt;/sup&gt;+2)(5x&lt;sup&gt;2&lt;/sup&gt;+2)(2x-3)

and since the first two factors are the same,
we can write:

(5x&lt;sup&gt;2&lt;/sup&gt;+2)&lt;sup&gt;2&lt;/sup&gt;(2x-3)

Edwin&lt;/pre&gt;</PRE>