<PRE><B>Question 746759</B>
A committee of 5 people is selected at random from a group of 16 men and 12 women. Find the probability that the committee contains at least 2 women. ==================================================
P(at least 2 women) = 1 - [P(no women) + P(1 women)]
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= 1 - [16C5/28C5 + (12C1*16C4)/28C12)]
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= 1 - [0.2667]
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= 0.7333
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Cheers,
Stan H.</PRE>