Question 746539
We are given the following problem

The length of a rectangle is 4 m. more than the width. The area is 30 m^2. Find the width and length. 

We have the following formula to solve

w(w+4) = 30
w^2+4w-30 = 0

now use quadratic formula

x = (-4 + or - sqrt(16-4(-30))) / 2

x = (-4 + or - sqrt(136)) / 2 = (-4 + or - 11.66) / 2

x = (-4 + 11.66) / 2 = 3.83
x = (-4 - 11.66) / 2 = -7.83