Question 746488
F(x) = 2x^4 - 8x + 3
F'(x) = 8x^3 - 8
F'(x) = 0
8x^3 - 8 = 0
8(x^3 - 1) = 0
  x = 1
Checking values before and after
x = 1 in F'(x) shows that this is 
a pt of inflexion

     Co.ords (1, -3)