Question 746377
In {{{ 2 }}} hrs, the slower car has a head start of
{{{ d[1] = 26*2 }}}
{{{ d[1] = 52 }}} mi
Let {{{ d }}} = the distance the faster car goes until
it catches the slower car.
Start a stopwatch when the faster car leaves
Let {{{ t }}} = the time on the stopwatch.
Equation for faster car:
(1) {{{ d = 52t }}}
Equation for slower car:
(2) {{{ d - 52 = 26t }}}
-------------------
substitute (1) into (2)
(2) {{{ 52t - 52 = 26t }}}
(2) {{{ 26t = 52 }}}
(2) {{{ t = 2 }}} 
It takes the faster car 2 hrs to catch the slower car
check:
(1) {{{ d = 52t }}}
(1) {{{ d = 52*2 }}}
(1) {{{ d = 104 }}} mi
and
(2) {{{ d - 52 = 26t }}}
(2) {{{ d - 52 = 26*2 }}}
(2) {{{ d = 52 + 52 }}}
(2) {{{ d = 104 }}} mi
OK