Question 746193
Please help me solve this equation.  I am having trouble finding all the steps.
log(16+2x)=log(x^2-4x)
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Is it finding x value in order for the function to be equal?
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If that so, since both side is in logarithm, you can eliminate log leaving:
{{{16+2x=x^2-4x}}} move 16 + 2x to the right,
{{{x^2-4x-2x-16=0}}}
{{{x^2-6x-16=0}}} the function is a quadratic equation, therefore to find x, use quadratic formula:{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
a = 1, b = -6 and c = -16
{{{x = (-(-6) +- sqrt( (-6)^2-4*1*(-16) ))/(2*1) }}}
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Therefore the answer are 8 and -2

{{{ graph( 300, 200, -5, 10, -30, 10, x^2-6x-16) }}}