Question 746153
{{{3log3(-5x)=3}}}


let's divide it by 3, then use inverse operations:


{{{(3log3(-5x))/3=3/3}}}



{{{log3(-5x)=1}}}


{{{3^(log3(-5x))=3^1}}}


{{{-5x=3}}}


so x=-3/5


:)