Question 746033
10.8% of American women have diabetes. Consider a sample of seventy-two ran-domly selected American women. 
a) What is the probability that exactly five of these women have diabetes?
P(x=5) = 72C5*(0.108)^5(0.892)^67 = 0.097
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b) What is the probability that more than ten of these women have diabetes?
P(10<= x <=72) = 1-P(0<= x <=9) = 1-binomcdf(72,0.108,9) = 0.247
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c) What is the probability that between seven and nine, inclusively, of these women have diabetes?
Find binomcdf(72,0.108,9)-binomcdf(72,0.108,6)
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Let N denote the number of women with diabetes in the sample. 
d) Determine the largest whole number n such that P{N &#8804; n} &#8804; 0.05.
n = 7
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e) Determine the smallest whole number n such that P{N &#8805; n} &#8804; 0.05.
n = 8
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f) Efficiently determine the expected value and standard deviation of  N.
u = np = 72*0.108 = 7.776
std = sqrt[7.776*0.892] = 2.634
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Cheers,
Stan H.
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