Question 745948
how do you solve log x + log (3x + 5)= 1

Properties of Logarithm:
log M + log N = log MN
log (10) = 1

So, {{{ log ((x)) + log ((3x+5)) = 1}}}
{{{log((x(3x+5))) = log ((10))}}}
{{{log ((3x^2+5x)) = log ((10))}}} eliminate log
{{{3x^2+5x = 10}}}
{{{3x^2+5x -10=0}}},it is a quadratic equation,

*[invoke quadratic "x", 3, 5, -10 ]
 Therefore, x = {1.1736,-2.8403}