Question 745833
when the sum of 4 and three times a positive number is subtracted from the square of the number, 0 results. Find the number

let x is the number:

when the sum of 4 and three times a positive number: {{{(4+3x)}}} 
is subtracted from the square of the number, 0 results: {{{x^2-(4+3x)=0}}}
{{{x^2-3x-4=0}}}

*[invoke quadratic "x", 1, -3, -4 ]

Therefore the positive number is:  4