Question 745683
Two integers are consecutive.
n & (n+1)
 If 5 is added to the first and 3 is subtracted from the second, the quotient of the resulting integers is 2 2/5.
{{{((n+5))/((n+1-3))}}} = {{{12/5}}}
which is
{{{((n+5))/((n-2))}}} = {{{12/5}}}
Cross multiply
12(n-2) = 5(n+5)
12n - 24 = 5n + 25
12n - 5n = 25 + 24
7n = 49
n = 49/7
n = 7 and 8 are the two integers
:
:
See if that works
12/5 = 2{{{2/5}}}