Question 745676
Fractions or otherwise, say h and k.  
{{{k-h=1/8}}} and {{{(2/3)*k=h}}}


{{{8(k-h)=1}}} and try substitution of h from the second equation.
{{{8(k-(2/3)*k)=1}}}
{{{8k-16k/3=1}}}
{{{24k-16k=3}}}
{{{8k=3}}}
{{{highlight(k=3/8)}}}


{{{h=(2/3)*(3/8)=2*3/(3*8)=2/8=1/4}}}
{{{highlight(h=1/4)}}}