Question 745623
A quarter of sum of two numbers is 16 and three times the diffence between the numbers is 30.

Let,
x - one number
y - the other
A quarter of sum of two numbers is 16: {{{(1/4)(x+y)=16}}}
three times the differences between the numbers is 30: {{{3(x-y)=30}}}
so, {{{(1/4)x+(1/4)y)=16}}}  and  {{{3x-3y)=30}}}

*[invoke linear "x", "y", 0.25, 0.25, 16, 3, -3, 30 ]
Therefore the two numbers are 37 and 27