Question 745532
log(7-x)=1+log(3x+2)   note: log(10)=1
log(7-x)=log(10)+log(3x+2)
log(7-x)=log[10(3x+2)] eliminate log
7-x=30x+20
{{{x=-13/31}}}

check:
{{{log((7-(-13/31)))=0.870366}}}
{{{log((3(-13/31)+2))=-0.129633}}}
{{{0.870366-(-0.129633)=1}}}