Question 745447
a) think any factor of 12, let say (3,4) or (2,6) and (1,12) this is the possible value of x since it is a quadratic equation,
The factor: {{{(x+3)(x+4)=x^2+3x+4x+12=x^2+7x+12}}}  so b here is 7
do this to other 2 possible value of x, you will get b=7 and b=13

b)this time think 2 numbers and their sum must be 6, let say (3,3) and (5,1)
again this is the possible value of x.
The factor: {{{(x+3)(x+3)=x^2+3x+3x+9=x^2+6x+9}}} so c here is 9
do this to other possible value of x, you will get c=5