<PRE><B>Question 64901</B>
If tim leaves at 10 am traveling down a road at 16 mph. And then at 10:30 his sister leaves traveling down the same road at 36 mph. how long will it take the sister to catch up?
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Tim DATA:
rate=16 mi/hr ; time=x hrs; distance= dr = 16x mi
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Sister DATA:
rate=36 mi/hr ; time = x-1/2 hr ; distane = dr = 36(x-(1/2))=36x-18 mi
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EQUATIOn:
distance = distance
16x=36x-18
20x=18
x=9/10 hr. or 54 minutes
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Stan H.</PRE>