Question 745229
A chemist has 20% and 60% solution of acid available. How many liters of each solution should be mixed to obtain 10 liters of a 30% acid solution?
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Equation:
0.20x + 0.60(10-x) = 0.30*10
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20x + 60*10 - 60x = 30*10
-40x = -30*10
x = (3/4)10
x = 7.5 liters (amt. of 20% solution needed)
10-x = 2.5 liters (amt. of 60% solution needed)
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Cheers,
Stan H.
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