<PRE><B>Question 745190</B>
a bag contains 2 red, 4 yellow, and 6 blue marbles. two marbles are drawn without replacement. find the probability that neither is red and neither is blue.
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They must both be yellow:
# of ways to succeed: 4C2 = (4*3)/(1*2) = 6
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# of possible outcomes: 12C2 = (12*11)/(1*2) = 66
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P(2 yellow) = 6/66 = 1/11
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Cheers,
Stan H.
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