Question 745091
Just wanna ask if you're asking the value of x here?
Anyway,
a) log (x² - 1) = log 3, you can eliminate the log
(x² - 1) = 3
x = 2

b)log base 2 (x + 3) + log base 2 (x - 3) = log base 2 7
log base 2[(x + 3)(x - 3)]= log base 2 7
(x + 3)(x - 3) = 7
x² - 9 = 7
x = 4

c)log base x + 1 (x² - x) = 2
Note: 
log base a (Answer) = Exponent
{{{ a^Exponent = Answer}}}
{{{ (x + 1)^2 = (x^2 - x)}}}
{{{x^2+2x+1=x^2 - x}}}
{{{2x+1=-x}}}
{{{x=-1/3}}}