<PRE><B>Question 745082</B>
A club has 20 males and 11 females. if 4 kids are chosen, what is the probability 2 will be male and 2 will be female?
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# of ways to succeed: 20C2*11C2 = 190*55 = 10450
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# of possible groups of 4: 31C4 = (31*30*29*28)/(1*2*3*4) = 31465
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p(2MALE and 2FEMALE) = 10450/31465 = 0.332
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Cheers,
Stan H.
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