Question 744921
rewrite in terms given...

Given log(base 3)10= 2.0959 find an approximation for each logarithm
a) 
log(base 3)1000
log(base 3)(10^3)
3*log(base 3)(10)
3*2.0959
6.2877
.
b) 
log(base 3)30
log(base 3)(3*10)
log(base 3)3 + log(base 3)(10)
1 + 2.0959
3.0959
.
c) 
log(base 3)√03
log(base 3)3^(1/3)
(1/3)log(base 3)3
(1/3)*1
1/3
.
d) 
log(base 3) (100/9) 
log(base 3)(100) - log(base 3)(9) 
log(base 3)(10^2) - log(base 3)(3^2) 
2log(base 3)(10) - 2log(base 3)(3) 
2(2.0959) - 2(1) 
4.1918 - 2
2.1918