Question 744772
A) 4cos x + sqrt 3= 2cos x

4cos x - 2cos x = -sqrt(3)

2cosx=-sqrt(3)
cosx= -sqrt(3)/2

x= 7pi/6



B) 2sin^2 x - 5 sin x= -2

2sin^2 x - 5 sin x +2=0

2sin^2 x - 4 sin x -sinx+2=0

2sinx(sinx-2)-1(sinx-2)=0
(sinx-2)(2sinx-1)=0

sinx = 2
or
sinx =1/2

between 0 & 2pi find x