Question 64837
Put each into a single fraction over single denominator:
{{{(2x^2/a) + a }}} = {{{(2x^2 + a^2)/a}}}
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{{{(y^2/a) - 3a}}} = {{{(y^2 - 3a^2)/a}}}
:
When you divide fractions, invert the dividing fraction and multiply:
Cancel the a's
{{{(2x^2 + a^2)/a}}} * {{{a/(y^2 - 3a^2)}}} = {{{(2x^2 + a^2)/(y^2 - 3a^2)}}} That's about as simple as you can get it: