Question 744756
a) log(base 5) x+2 = 1- log(base 5) x-2

log(base 5) x+2 +log(base 5) x-2=1

log(base 5) ((x+2)(x-2)) =log(base5)5

x^2-4=5

x^2=9
x= +/- 3

ignore negative
x=3




b) log(base 5)x^2-4 = 1

log(base 5)x^2-4 = log (base5)5

x^2-4=5
x^2=9
x= +/-3