Question 744763
given:
cylindrical tennis ball container can contain maximum three ball stacked
on one another

the top and bottom ball also touch the lid and the base of the container
respectively - means, the sum of diameters of the three tennis balls is equal to height of the cylindrical container


a tennis ball is a sphere and the volume of a sphere is {{{V=(4/3)pi*r^3}}}; so, if the volume of a tennis ball is {{{240cm^3}}},then

{{{240cm^3=(4/3)pi*r^3}}}

{{{240cm^3/((4/3)pi)=r^3}}}

{{{(3*240cm^3)/(4*3.14)=r^3}}}

{{{(720cm^3)/12.56=r^3}}}

{{{57.33cm^3=r^3}}}

{{{root(3,57.33cm^3)=r}}}

{{{3.86cm=r}}}........this is radius and we need diameter:

{{{d=2r=2*3.86cm=7.72cm}}}

now we know that the height of the cylindrical container is {{{h=3d=3*7.72cm=23.16cm}}} and we know the radius (which is equal to a radius of the tennis ball) is {{{r=3.86cm}}}


 the volume of the container is:

{{{V1=r^2pi*h}}}

{{{V1=(3.86cm)^2*3.14*23.16cm}}}

{{{V1=14.8996cm^2*72.7224cm}}}


{{{V1=1083.54cm^3}}}